20x^2-49x-30=0

Solution for 20x^2-49x-30=0 equation:

20x^2-49x-30=0

a = 20; b = -49; c = -30;
Δ = b2-4ac
Δ = -492-4·20·(-30)
Δ = 4801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{4801}}{2*20}=\frac{49-\sqrt{4801}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{4801}}{2*20}=\frac{49+\sqrt{4801}}{40}
$